Basic Chemistry

basic chemistry

Welcome to our Basic Chemistry tutorial series. We specifically designed this series as a help for those students who want to have a comprehensive intro to chemistry and to do it step-by-step. Feel free to give us your feedback, criticism, and suggestions, so we can make this, and all following tutorials to be absolutely awesome.

What you’re going to learn in this tutorial

We start the series with a quick introduction to the metric system and the SI units. You will use the metric system for almost every problem in your chemistry course, so it is super important to have a strong understanding of it.

We then will go into the exploration of the difference between the atoms, elements, compounds, substances, and mixtures. This is one of the foundational topics for any chemistry student to master.

How you can check your understanding

Each lesson has a quiz associated with the specific lesson topic. You can attempt the quizzes as many times as you like to make sure that have a solid understanding of the topic. The final quiz has questions from all topics.

NOTE: most of our tutorials are currently under redevelopment. We’re sorry if you don’t see the one you want. Let us know what tutorial you want to see, and we’ll try to upload as soon as possible.

4 thoughts on “Basic Chemistry”

  1. kayla schreiber

    i preformed titrations with 0.1%DCPIP but am unclear on how to calculate the moles of DCPIP. does the 0.1% mean the concentration is 0.1 or is that a dilution factor.

    1. 0.1% most likely refers to percent-by-mass concentration, which means that 100g of the solution contains 0.1g of DCPIP. At such low concentration, provided there are no other components in the solution, the mass of solution will = to the volume since water density =1. So, it is, essentially, 0.1g of DCPIP in 100mL of a solution. So, if you know how many mL of the DCPIP solution you’ve used, you can calculate the mass in grams of DCPIP used. From there you can calculate the moles. We have a tutorial on how to convert mass into moles here.

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